How do I zip the contents of a folder using python (version 2.5)?

Question

Once I have all the files I require in a particular folder, I would like my python script to zip the folder contents.

Is this possible?

And how could I go about doing it?

Answer 1

On python 2.7 you might use: shutil.make_archive(base_name, format[, root_dir[, base_dir[, verbose[, dry_run[, owner[, group[, logger]]]]]]]).

base_name archive name minus extension

format format of the archive

root_dir directory to compress.

For example

 shutil.make_archive(target_file, format="bztar", root_dir=compress_me)     

Answer 2

Adapted version of the script is:

#!/usr/bin/env python from __future__ import with_statement from contextlib import closing from zipfile import ZipFile, ZIP_DEFLATED import os  def zipdir(basedir, archivename):     assert os.path.isdir(basedir)     with closing(ZipFile(archivename, "w", ZIP_DEFLATED)) as z:         for root, dirs, files in os.walk(basedir):             #NOTE: ignore empty directories             for fn in files:                 absfn = os.path.join(root, fn)                 zfn = absfn[len(basedir)+len(os.sep):] #XXX: relative path                 z.write(absfn, zfn)  if __name__ == '__main__':     import sys     basedir = sys.argv[1]     archivename = sys.argv[2]     zipdir(basedir, archivename) 

Example:

C:\zipdir> python -mzipdir c:\tmp\test test.zip 

It creates 'C:\zipdir\test.zip' archive with the contents of the 'c:\tmp\test' directory.