How do I zip keys with individual values in my lists in python?

Question

I am importing a matrix, turning the first row into keys, and turning the rest of the rows into values. I want to zip the keys with each value and put them in a dictionary.

ex:

If I have the following:

k = ['a', 'b']
v = [[1,2], [3,4]]

I want to take each value in v (for x in v) and zip them (k and x) then convert to a dictionary.

Then I will add the dictionaries to a list of dictionaries.

At the end I should have:

dicts = [{'a':1, 'b':2}, {'a':3, 'b':4}]

Right now, I am only zipping my rows with my keys. How do I fix this?

matrix_filename = raw_input("Enter the matrix filename:  ")  
matrix = [i.strip().split() for i in open(matrix_filename).readlines()]  
keys = matrix[0]  
vals= (matrix[1:])  
N=len(vals)  

dicts = []  

for i in range(1,N):  
    for j in range(1,N):  
        vals[i-1][j-1] = int(matrix[i][j])  
        dicts = dict(zip(keys,vals))  

Answer 1

>>> [dict(zip(k, x)) for x in v]
[{'a': 1, 'b': 2}, {'a': 3, 'b': 4}]

Answer 2

using itertools.cycle():

In [51]: from itertools import *

In [52]: cyc=cycle(k)

In [53]: [{next(cyc):y for y in x} for x in v]
Out[53]: [{'a': 1, 'b': 2}, {'a': 3, 'b': 4}]