How do I work with images in Bokeh (Python)

Question

For example you can plot an image in matplotlib using this code:

%matplotlib inline
import matplotlib.pyplot as plt
import matplotlib.image as mpimg
img=mpimg.imread('image.png')
plt.imshow(img)

Is something like this possible with Bokeh(0.10)?

Answer 1

You can use the ImageURL glyph (image_url plot method)to load images locally or from the web.

from bokeh.plotting import figure, show, output_file

output_file('image.html')

p = figure(x_range=(0,1), y_range=(0,1))
p.image_url(url=['tree.png'], x=0, y=1, w=0.8, h=0.6)
## could also leave out keywords
# p.image_url(['tree.png'], 0, 1, 0.8, h=0.6)  
show(p)

One gotcha - if you graph only an image (and no other data), you'll have to explicitly set the plot ranges.

Here's the docs:

http://docs.bokeh.org/en/latest/docs/reference/models/glyphs.html#bokeh.models.glyphs.ImageURL

Answer 2

The earlier answer was helpful. However, I wanted an image only option without any additional object. So, adding the answer for Bokeh version 0.12.0 and removed all the grids, axes and toolbar.

from bokeh.plotting import figure, curdoc
from bokeh.models import ColumnDataSource, Range1d

bosch_logo = "static/tree.jpg"
logo_src = ColumnDataSource(dict(url = [bosch_logo]))

page_logo = figure(plot_width = 500, plot_height = 500, title="")
page_logo.toolbar.logo = None
page_logo.toolbar_location = None
page_logo.x_range=Range1d(start=0, end=1)
page_logo.y_range=Range1d(start=0, end=1)
page_logo.xaxis.visible = None
page_logo.yaxis.visible = None
page_logo.xgrid.grid_line_color = None
page_logo.ygrid.grid_line_color = None
page_logo.image_url(url='url', x=0.05, y = 0.85, h=0.7, w=0.9, source=logo_src)
page_logo.outline_line_alpha = 0 
curdoc().add_root(page_logo)