I am new to R and am working on a data set including nominal, ordinal and metric data.
Therefore I am using the gower distance. In the next step I use this distance with hclust(x, method="complete")
to create clusters based on this distance.
Now I want to know how I can put different weights on variables in the gower distance. The documentation says:
daisy(x, metric = c("euclidean", "manhattan", "gower"), stand = FALSE, type = list(), weights = rep.int(1, p))
So there is a way, but I am unsure about the syntax (weights = ...
).
The documentation of weights
and rep.int
, did not help.
I also didn't find any other helpful explanation.
I would be very glad, if some one can help out.
Not sure if this is what you are getting at, but...
Let's say you have 5 variables, e.g. 5 columns in your data frame or matrix. Then weights
would be a vector of length=5
containing the weights for the corresponding columns.
The notation weights=rep.int(1,p)
in the documentation simply means that the default value of weights is a vector of length p that has all 1's, eg. the weights are all equal to 1. Elsewhere in the documentation it explains that p is the number of columns.
Also, note that daisy(...)
produces a dissimilarity matrix. This is what you use in hclust(...)
. So if x
is a data frame or matrix with five columns for your variables, then:
d <- daisy(x, metric="gower", weights=c(1,2,3,4,5))
hc <- hclust(d, method="complete")
EDIT (Response to OP's comments)
The code below shows how the clustering depends on the weights.
clust.anal <- function(df,w,h) {
require(cluster)
d <- daisy(df, metric="gower", weights=w)
hc <- hclust(d, method="complete")
clust <- cutree(hc,h=h)
plot(hc, sub=paste("weights=",paste(wts,collapse=",")))
rect.hclust(hc,h=0.8,border="red")
}
df <- read.table("ExampleClusterData.csv", sep=";",header=T)
df[1] <- factor(df[[1]])
df[2] <- factor(df[[2]])
# weights increase with col number...
wts=c(1,2,3,4,5,6,7)
clust.anal(df,wts,h=0.8)
# weights decrease with col number...
wts=c(7,6,5,4,3,2,1)
clust.anal(df,wts,h=0.8)
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