I am using an XML configuration file that is loaded into my Java application using ApplicationContext.
The XML configuration file resolves its properties by reading from several property files using PropertyPlaceholderConfigurer.
I want to make each property file optional. I thought that this is done by setting ignoreUnresolsvablePlaceholders to true, however I am getting the following exception when I run the application (db-default.properties exists but db.properties does not):
Exception in thread "main" org.springframework.beans.factory.BeanInitializationException: Could not load properties; nested exception is java.io.FileNotFoundException: class path resource [db.properties] cannot be opened because it does not exist
This is what my XML configuration looks like:
<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/context
http://www.springframework.org/schema/context/spring-context-3.0.xsd">
<bean id="placeholder-configurer-1" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="order" value="1"/>
<property name="ignoreUnresolvablePlaceholders" value="true"/>
</bean>
<bean id="placeholder-configurer-2" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="order" value="2"/>
<property name="ignoreUnresolvablePlaceholders" value="true"/>
<property name="location" value="classpath:/db-default.properties"/>
</bean>
<bean id="placeholder-configurer-3" class="org.springframework.beans.factory.config.PropertyPlaceholderConfigurer">
<property name="order" value="3"/>
<property name="ignoreUnresolvablePlaceholders" value="true"/>
<property name="locations">
<list>
<value>classpath:/db.properties</value>
</list>
</property>
</bean>
<bean id="MyDataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close">
<property name="driverClassName" value="${jdbc.driver}"/>
<property name="url" value="${jdbc.url}"/>
<property name="username" value="${jdbc.username}"/>
<property name="password" value="${jdbc.password}"/>
</bean>
</beans>
What do I need to do to make db.properties an optional property file?
You can use properties files, YAML files, environment variables and command-line arguments to externalize configuration. Property values can be injected directly into your beans using the @Value annotation, accessed via Spring's Environment abstraction or bound to structured objects.
Step 1 − After creating an executable JAR file, run it by using the command java –jar <JARFILE>. Step 2 − Use the command given in the screenshot given below to change the port number for Spring Boot application by using command line properties.
<property name="ignoreResourceNotFound" value="true"/>
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