I think this might be a pretty simple question, but I haven't been able to figure it out yet. If I've got a 2-dimensional array like so:
int[,] matris = new int[5, 8] {
{ 1, 2, 3, 4, 5,6,7,8 },
{9,10,11,12,13,14,15,16},
{ 17,18,19,20,21,22,23,24 },
{ 25,26,27,28,29,30,31,32 },
{ 33,34,35,36,37,38,39,40 },
};
and a for loop, like this:
for (int r = 0; r < 5; r++)
{
for (int j = 0; j < 8; j++)
Console.Write("{0} ", matris[r, j]);
Console.WriteLine();
}
So with this code I am printing out the multi dimensional array. But how do I print out a transpose of the array?
For example, transpose() is useful when a 3D array is a group of 2D arrays. If the data of matrices are stored as a 3D array of shape (n, row, column) , all matrices can be transposed as follows. If the shape is (row, column, n) , you can do as follows.
The transpose of a 1D array is still a 1D array! (If you're used to matlab, it fundamentally doesn't have a concept of a 1D array. Matlab's "1D" arrays are 2D.) If you want to turn your 1D vector into a 2D array and then transpose it, just slice it with np.
Transpose of a matrix is obtained by changing rows to columns and columns to rows. In other words, transpose of A[N][M] is obtained by changing A[i][j] to A[j][i].
Just change your loops with each other:
for (int j = 0; j < 8; j++)
{
for (int r = 0; r < 5; r++)
Console.Write("{0} ", matris[r, j]);
Console.WriteLine();
}
Creating new array:
var newArray = new int[8, 5];
for (int j = 0; j < 8; j++)
for (int r = 0; r < 5; r++)
newArray[j, r] = matris[r, j];
You just need to do this:
for (int r = 0; r < 8; r++)
{
for (int j = 0; j < 5; j++)
Console.Write("{0} ", matris[j, r]);
Console.WriteLine();
}
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