I do want to give a default value for the positional parameter as in the comment in the code, but the compiler complains. The code as it is compiles fine. I use boost 1.46.1 and g++
int main(int argc, char *argv[]) {
namespace po = boost::program_options;
po::positional_options_description p;
p.add("path", -1);
po::options_description desc("Options");
std::vector<std::string> vec_str;
std::string str;
desc.add_options()
("foo,f", po::value< std::string >()->default_value(str), "bar")
//("path,p", po::value< std::vector<std::string> >()->default_value(vec_str), "input files.")
("path,p", po::value< std::vector<std::string> >(), "input files.")
;
po::variables_map vm;
po::store(po::command_line_parser(argc, argv).options(desc).positional(p).run(), vm);
po::notify(vm);
}
I need to give a textual representation of the default value, see http://lists.boost.org/boost-users/2010/01/55054.php.
I.e. the following line works:
("path,p", po::value< std::vector<std::string> > ()->default_value(std::vector<std::string>(), ""), "input files.")
I guess this is needed for the help output, which could in my example
std::cout << desc << std::endl;
Since the compiler doesn't know how to overload the operator<<()
for vector<string>
, it complains.
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