I need to do 2 things: run a batch file (works fine), and run a command (does not work). The method for the command throws the exception 'file not found'. If I open a cmd window, and type the command, it works perfectly.
private static void Rescan()
{
//System.Diagnostics.ProcessStartInfo psi = new System.Diagnostics.ProcessStartInfo("DEVCON ReScan");
//psi.RedirectStandardOutput = true;
//psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
//psi.UseShellExecute = false;
//System.Diagnostics.Process proc = System.Diagnostics.Process.Start(psi);
System.Diagnostics.Process proc = new System.Diagnostics.Process();
proc.StartInfo.FileName = "DEVCON ReScan";
proc.StartInfo.RedirectStandardError = true;
proc.StartInfo.RedirectStandardOutput = true;
proc.StartInfo.UseShellExecute = false;
proc.Start();
proc.WaitForExit();
System.IO.StreamReader myOutput = proc.StandardOutput;
proc.WaitForExit(4000);
if (proc.HasExited)
{
string output = myOutput.ReadToEnd();
FileIO.WriteLog(_writePath, output);
}
}
The commented code also throws the same exception.
DEVCON ReScan is really the name of the executable? I guess the executable is DEVCON, while ReScan is a parameter. This means you have to set StartInfo.FileName to "DEVCON" and StartInfo.Arguments to "ReScan".
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