I have loaded a data file into a Python pandas dataframe. I has a datetime column of the format 2015-07-18 13:53:33.280
.
What I need to do is create a new column that rounds this out to its nearest quarter hour. So, the date above will be rounded to 2015-07-18 13:45:00.000
.
How do I do this in pandas? I tried using the solution from here, but get an 'Series' object has no attribute 'year'
error.
Round time to nearest hour ( TIME(1,0,0) = 1/24 representing an hour) and add a zero time value to ensure the expression is cast as a Time. M: There isn't an equivalent of MROUND in M, so instead multiply the time by 24 to express it as a number of hours, then round, then divide by 24 and convert to a Time type.
You can use round(freq)
. There is also a shortcut column.dt
for datetime functions access (as @laurens-koppenol suggests).
Here's one-liner:
df['old column'].dt.round('15min')
String aliases for valid frequencies can be found here. Full working example:
In [1]: import pandas as pd In [2]: df = pd.DataFrame([pd.Timestamp('2015-07-18 13:53:33.280'), pd.Timestamp('2015-07-18 13:33:33.330')], columns=['old column']) In [3]: df['new column']=df['old column'].dt.round('15min') In [4]: df Out[4]: old column new column 0 2015-07-18 13:53:33.280 2015-07-18 14:00:00 1 2015-07-18 13:33:33.330 2015-07-18 13:30:00
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