How do I reverse a sublist in a list in place?

Question

I'm supposed to create a function, which input is a list and two numbers, the function reverses the sublist which its place is indicated by the two numbers. for example this is what it's supposed to do:

>>> lst = [1, 2, 3, 4, 5] 
>>> reverse_sublist (lst,0,4) 
>>> lst  [4, 3, 2, 1, 5]

I created a function and it works, but I'm not sure is it's in place. This is my code:

def reverse_sublist(lst,start,end):
    sublist=lst[start:end]
    sublist.reverse()
    lst[start:end]=sublist
    print(lst)

Answer 1

def reverse_sublist(lst,start,end):
    lst[start:end] = lst[start:end][::-1]
    return lst

Answer 2

Partial reverse with no temporary list (replace range with xrange if you use Python 2):

def partial_reverse(list_, from_, to):
    for i in range(0, int((to - from_)/2)):
        (list_[from_+i], list_[to-i]) = (list_[to-i], list_[from_+i])

list_ = [1, 2, 3, 4, 5, 6, 7, 8]
partial_reverse(list_, 3, 7)
print(list_)

Answer 3

Easiest way to reverse a list in a partial or complete manner.

listVar = ['a','b','c','d']
def listReverse(list,start,end):
    while(start<end):
        temp = list[start]
        list[start] = list[end] #Swaping
        list[end]=temp
        start+=1
        end-=1
    print(list)


listReverse(listVar,1,3)

Output : - ['a', 'd', 'c', 'b']