I want to return an instance of an object of same type of the Class object passed in. The type passed in can be ANYTHING. Is there a way to do this with Generics?
To clarify -- I don't want the caller of the method to not have to cast to the Class of the object they passed in
For example,
public Object<Class> getObject(Class class)
{
// Construct an instance of an object of type Class
return object;
}
// I want this:
MyClass myObj = getObject(MyClass.class);
// Not this (casting):
MyClass myObj = (MyClass)getObject(MyClass.class);
I assume you want to create a new instance of that class. This would not be possible using generics (you can't call new T()
) and would also be quite limited using reflection.
The reflection approach could be:
//class is a reserved word, so use clazz
public <T> T getObject(Class<T> clazz) {
try {
return clazz.newInstance();
}
catch( /*a multitude of exceptions that can be thrown by clazz.newInstance()*/ ) {
//handle exception
}
}
Note that this only works if the class has a no-argument constructor.
However, the question would by why you need that instead of just calling new WhatEverClassYouHave()
.
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