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I want to remove trailing white spaces and tabs from my code without removing empty lines.
I tried:
\s+$ and:
([^\n]*)\s+\r\n But they all removed empty lines too. I guess \s matches end-of-line characters too.
UPDATE (2016):
Nowadays I automate such code cleaning by using Sublime's TrailingSpaces package, with custom/user setting:
"trailing_spaces_trim_on_save": true It highlights trailing white spaces and automatically trims them on save.
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Type M-x delete-trailing-whitespace to delete all trailing whitespace. This command deletes all extra spaces at the end of each line in the buffer, and all empty lines at the end of the buffer; to ignore the latter, change the variable delete-trailing-lines to nil .
Trimming WhitespaceSearch for [ \t]+$ to trim trailing whitespace. Do both by combining the regular expressions into ^[ \t]+|[ \t]+$. Instead of [ \t] which matches a space or a tab, you can expand the character class into [ \t\r\n] if you also want to strip line breaks. Or you can use the shorthand \s instead.
Use the String. replace() method to remove all whitespace from a string, e.g. str. replace(/\s/g, '') . The replace() method will remove all whitespace characters by replacing them with an empty string.
strip() Python String strip() function will remove leading and trailing whitespaces. If you want to remove only leading or trailing spaces, use lstrip() or rstrip() function instead.
Try just removing trailing spaces and tabs:
[ \t]+$ To remove trailing whitespace while also preserving whitespace-only lines, you want the regex to only remove trailing whitespace after non-whitespace characters. So you need to first check for a non-whitespace character. This means that the non-whitespace character will be included in the match, so you need to include it in the replacement.
Regex: ([^ \t\r\n])[ \t]+$
Replacement: \1 or $1, depending on the IDE
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