How do I remove a list item from a dict value?

Question

I have a host dict that contains a hostname key, and list values. I would like to be able to remove any item of fruit_ from the list of each value.

host = { 
  'abc.com': ['fruit_apple', 'fruit_orange', 'veg_carrots'], 
  '123.com': None, 
  'foo.com': ['fruit_tomatoes', 'veg_potatoes']
}

for v in host.values():
  if v is not None:
    for x in v:
      try:
        # creating my filter
        if x.startswith('fruit_'):
        # if x finds my search, get, or remove from list value
         host(or host.value()?).get/remove(x)# this is where i'm stuck
        print(hr.values(#call position here?)) # prove it
      except:
        pass

I'm stuck around the commented area, I feel like I'm missing another iteration (new list somewhere?), or maybe I'm not understanding how to write the list value back. Any direction would be helpful.

Answer 1

A better way to filter items from a list is to use list comprehension with a filtering condition and create a new list, like this.

host = {
    'abc.com': ['fruit_apple', 'fruit_orange', 'veg_carrots'],
    '123.com': [None],
    '456.com': None,
    'foo.com': ['fruit_tomatoes', 'veg_potatoes']
}


def reconstruct_list(vs):
    return vs if vs is None else [
        v for v in vs if v is None or not v.startswith('fruit_')
    ]


print({k: reconstruct_list(vs) for k, vs in host.items()})

Output

{'abc.com': ['veg_carrots'], '123.com': [None], '456.com': None, 'foo.com': ['veg_potatoes']}

In this particular case, individual values of the lists are filtered and a new dictionary object is created with dictionary comprehension.