For example if I have YAML file with
en:
questions:
new: 'New Question'
other:
recent: 'Recent'
old: 'Old'
This would end up as a json object like
{
'questions.new': 'New Question',
'questions.other.recent': 'Recent',
'questions.other.old': 'Old'
}
Since the question is about using YAML files for i18n on a Rails app, it's worth noting that the i18n
gem provides a helper module I18n::Backend::Flatten
that flattens translations exactly like this:
test.rb
:
require 'yaml'
require 'json'
require 'i18n'
yaml = YAML.load <<YML
en:
questions:
new: 'New Question'
other:
recent: 'Recent'
old: 'Old'
YML
include I18n::Backend::Flatten
puts JSON.pretty_generate flatten_translations(nil, yaml, nil, false)
Output:
$ ruby test.rb
{
"en.questions.new": "New Question",
"en.questions.other.recent": "Recent",
"en.questions.other.old": "Old"
}
require 'yaml'
yml = %Q{
en:
questions:
new: 'New Question'
other:
recent: 'Recent'
old: 'Old'
}
yml = YAML.load(yml)
translations = {}
def process_hash(translations, current_key, hash)
hash.each do |new_key, value|
combined_key = [current_key, new_key].delete_if { |k| k.blank? }.join('.')
if value.is_a?(Hash)
process_hash(translations, combined_key, value)
else
translations[combined_key] = value
end
end
end
process_hash(translations, '', yml['en'])
p translations
@Ryan's recursive answer is the way to go, I just made it a little more Rubyish:
yml = YAML.load(yml)['en']
def flatten_hash(my_hash, parent=[])
my_hash.flat_map do |key, value|
case value
when Hash then flatten_hash( value, parent+[key] )
else [(parent+[key]).join('.'), value]
end
end
end
p flatten_hash(yml) #=> ["questions.new", "New Question", "questions.other.recent", "Recent", "questions.other.old", "Old"]
p Hash[*flatten_hash(yml)] #=> {"questions.new"=>"New Question", "questions.other.recent"=>"Recent", "questions.other.old"=>"Old"}
Then to get it into json format you just need to require 'json' and call the to_json method on the hash.
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