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I'm writing a program in which I need to take input from the keyboard. I need to take a number in, yet I'm not sure if it's an int or a double. Here's the code that I have (for that specific part):
import java.io.*;
import java.util.*;
//...
Scanner input = new Scanner(System.in);
int choice = input.nextInt();
I know I can get a String and do parseInt() or parseDouble(), but I don't know which one it'll be.
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The nextDouble() method of java. util. Scanner class scans the next token of the input as a Double. If the translation is successful, the scanner advances past the input that matched.
The readDouble() method of DataInputStream class in Java is used to read eight input bytes and returns a double value. This method reads the next eight bytes from the input stream and interprets it into double type and returns. Specified By: This method is specified by readDouble() method of DataInput interface.
parseDouble(stringInput); when you scan the input as a String you can then parse it to see if it is a double. But, if you wrap this static method call in a try-catch statement, then you can handle the situation where a double value is not parsed.
Well, ints are also doubles so if you assume that everything is a double you will be OK with your logic. Like this:
import java.io.*;
import java.util.*;
Scanner input = new Scanner(System.in);
double choice = input.nextDouble();
It only get complex if you needed the input to be an integer for whatever reason. And then, parseInt() to test for int would be just fine.
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