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I have made a line graph in python with pyplot/matplotlib:
import matplotlib.pyplot as plt
import math
import numpy as np
alphabet = range(0, 25)
firstLine = [letter + 65 for letter in alphabet]
secondLine = [letter + 97 for letter in alphabet]
plt.plot(alphabet, firstLine, '-b', label='ASCII value of capital.')
plt.plot(alphabet, secondLine, '--g', label='ASCII value of lowercase.')
plt.xlabel('Letter in Alphabet')
plt.ylabel('ASCII Value')
plt.title('ASCII value vs. Letter')
plt.legend()
plt.show()
On my x-axis, it current scales by numbers. However, I want increments on the x-axis to be labeled by letters (a, b, c, d) instead of say 0, 5, 10... Specifically, I want the letter 'a' to map to 0, 'b' to map to 1, etc.
How do I make pyplot do that?
879
The order in which you write x- and y-coordinates in an ordered pair is very important. The x-coordinate always comes first, followed by the y-coordinate. As you can see in the coordinate grid below, the ordered pairs (3,4) and (4,3) are two different points!
The x coordinate always comes first, followed by the y coordinate. That is why (3, 4) is not the same as (4, 3). (3, 4) refers to a point three units to the right of zero and four units above zero. (4, 3) refers to a point four units to the right of zero and three units above zero.
The three-dimensional rectangular coordinate system is the one-to-one correspondence be- tween each point P in three-dimensional space, or xyz-space, and an ordered triple (x, y, z) in 3. The numbers x, y and z are the x-, y- and z-coordinates of P. The origin O is the point with coordinates (0,0,0).
Use the xticks function. If you do pyplot.xticks([0, 1, 2, 3], ['a', 'b', 'c', 'd']) then it will have axis marks at 0, 1, 2, and 3, and they will be labeled a, b, c, and d. You can also use np.arange to quickly create the range of numbers you want.
71
I've used plt.xticks(range(26), [chr(97 + x) for x in xrange(26)]) below.
NOTE: you should change your alphabet = range(0, 25) to alphabet = range(26) because otherwise you are missing out on 'z'.
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