How do I loop through a list and remove an item in groovy?

Question

I'm trying to figure out how to remove an item from a list in groovy from within a loop.

static main(args) {
   def list1 = [1, 2, 3, 4]
   for(num in list1){
   if(num == 2)
      list1.remove(num)
   }
   println(list1)
}

Answer 1

list = [1, 2, 3, 4]
newList = list.findAll { it != 2 }

Should give you all but the 2

Of course you may have a reason for requiring the loop?

Answer 2

If you want to remove the item with index 2, you can do

list = [1,2,3,4]
list.remove(2)
assert list == [1,2,4]

// or with a loop
list = [1,2,3,4]
i = list.iterator()
2.times {
    i.next()
}
i.remove()
assert list == [1,2,4]

If you want to remove the (first) item with value 2, you can do

list = [1,2,3,4]
list.remove(list.indexOf(2))
assert list == [1,3,4]

// or with a loop
list = [1,2,3,4]
i = list.iterator()
while (i.hasNext()) {
    if (i.next() == 2) {
        i.remove()
        break
    }
}
assert list == [1,3,4]