How do I list all of the files in a commit?

Question

I am looking for a simple Git command that provides a nicely formatted list of all files that were part of the commit given by a hash (SHA-1), with no extraneous information.

I have tried:

git show a303aa90779efdd2f6b9d90693e2cbbbe4613c1d 

Although it lists the files, it also includes unwanted diff information for each.

Is there another git command that will provide just the list I want, so that I can avoid parsing it from the git show output?

Answer 1

Preferred Way (because it's a plumbing command; meant to be programmatic):

$ git diff-tree --no-commit-id --name-only -r bd61ad98 index.html javascript/application.js javascript/ie6.js 

Another Way (less preferred for scripts, because it's a porcelain command; meant to be user-facing)

$ git show --pretty="" --name-only bd61ad98     index.html javascript/application.js javascript/ie6.js 

---

• The --no-commit-id suppresses the commit ID output.
• The --pretty argument specifies an empty format string to avoid the cruft at the beginning.
• The --name-only argument shows only the file names that were affected (Thanks Hank). Use --name-status instead, if you want to see what happened to each file (Deleted, Modified, Added)
• The -r argument is to recurse into sub-trees