How do I iterate through the digits of an integer? [duplicate]

Question

Possible Duplicate:
Turning long fixed number to array Ruby

Well, I have to iterate over the digits of a integer in Ruby. Right now I was just splitting it up into an array, and then iterating over that. However I was wondering if there was a faster way to do this?

Answer 1

The shortest solution probably is:

1234.to_s.chars.map(&:to_i) #=> [1, 2, 3, 4] 

A more orthodox mathematical approach:

class Integer   def digits(base: 10)     quotient, remainder = divmod(base)     quotient == 0 ? [remainder] : [*quotient.digits(base: base), remainder]   end end  0.digits #=> [0] 1234.digits #=> [1, 2, 3, 4] 0x3f.digits(base: 16) #=> [3, 15]