How do I include output parameters in a function with Typescript?

Question

Is it possible to include output parameters in a function with TypeScript? Something like Func1(string val1, int out k1, int out k2) in C#.

Answer 1

Not currently.

You can return an object that can contain more than one property.

return { k1: 5, k2: 99 }; 

You can combine this with destructuring so the intermediate object becomes invisible...

function myFunction() {     return { k1: 5, k2: 99 }; }  const { k1, k2 } = myFunction();  console.log(k1); console.log(k2); 

You could also achieve the same with a tuple, but this is pretty readable.