I would like to upload data I generated at runtime in Ruby, something like feeding the upload from a block.
All examples I found only show how to stream a file that must be on disk prior to the request but I do not want to buffer the file.
What is the best solution besides rolling my own socket connection?
This a pseudocode example:
post_stream('127.0.0.1', '/stream/') do |body|
generate_xml do |segment|
body << segment
end
end
Code that works.
require 'thread'
require 'net/http'
require 'base64'
require 'openssl'
class Producer
def initialize
@mutex = Mutex.new
@body = ''
@eof = false
end
def eof!()
@eof = true
end
def eof?()
@eof
end
def read(size)
@mutex.synchronize {
@body.slice!(0,size)
}
end
def produce(str)
if @body.empty? && @eof
nil
else
@mutex.synchronize { @body.slice!(0,size) }
end
end
end
data = "--60079\r\nContent-Disposition: form-data; name=\"file\"; filename=\"test.file\"\r\nContent-Type: application/x-ruby\r\n\r\nthis is just a test\r\n--60079--\r\n"
req = Net::HTTP::Post.new('/')
producer = Producer.new
req.body_stream = producer
req.content_length = data.length
req.content_type = "multipart/form-data; boundary=60079"
t1 = Thread.new do
producer.produce(data)
producer.eof!
end
res = Net::HTTP.new('127.0.0.1', 9000).start {|http| http.request(req) }
puts res
There's a Net::HTTPGenericRequest#body_stream=( obj.should respond_to?(:read) )
You use it more or less like this:
class Producer
def initialize
@mutex = Mutex.new
@body = ''
end
def read(size)
@mutex.synchronize {
@body.slice!(0,size)
}
end
def produce(str)
@mutex.synchronize {
@body << str
}
end
end
# Create a producer thread
req = Net::HTTP::Post.new(url.path)
req.body_stream = producer
res = Net::HTTP.new(url.host, url.port).start {|http| http.request(req) }
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With