I wrote some statements like below:
os.system(cmd) #do something subprocess.call('taskkill /F /IM exename.exe')
both will pop up a console.
How can I stop it from popping up the console?
Simply save it with a . pyw extension. This will prevent the console window from opening.
os. system is equivalent to Unix system command, while subprocess was a helper module created to provide many of the facilities provided by the Popen commands with an easier and controllable interface. Those were designed similar to the Unix Popen command.
Description. Python method popen() opens a pipe to or from command. The return value is an open file object connected to the pipe, which can be read or written depending on whether mode is 'r' (default) or 'w'. The bufsize argument has the same meaning as in open() function.
The process STARTUPINFO
can hide the console window:
si = subprocess.STARTUPINFO() si.dwFlags |= subprocess.STARTF_USESHOWWINDOW #si.wShowWindow = subprocess.SW_HIDE # default subprocess.call('taskkill /F /IM exename.exe', startupinfo=si)
Or set the creation flags to disable creating the window:
CREATE_NO_WINDOW = 0x08000000 subprocess.call('taskkill /F /IM exename.exe', creationflags=CREATE_NO_WINDOW)
The above is still a console process with valid handles for console I/O (verified by calling GetFileType
on the handles returned by GetStdHandle
). It just has no window and doesn't inherit the parent's console, if any.
You can go a step farther by forcing the child to have no console at all:
DETACHED_PROCESS = 0x00000008 subprocess.call('taskkill /F /IM exename.exe', creationflags=DETACHED_PROCESS)
In this case the child's standard handles (i.e. GetStdHandle
) are 0, but you can set them to an open disk file or pipe such as subprocess.DEVNULL
(3.3) or subprocess.PIPE
.
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