I am using jcrop to crop the image in my php application.I am using below code to pass the coordinate values and image path using ajax,
function checkCoords(index) { if (parseInt(jQuery('#w').val())){ jQuery.ajax({ type : "POST", cache: false, dataType: 'html', data : { x : jQuery('#x').val(), y : jQuery('#y').val(), w : jQuery('#w').val(), h : jQuery('#h').val(), image_path : jQuery('#jc-hidden-image'+index).attr('src') }, url : BASE_URL+'apps/configure/cropimage', success : function(response) { jQuery(".preview_crop").html(response); } }); } else{ alert('Please select a crop region then press Crop button.'); }
In Controller, I use the ajax value as below,
public function cropimageAction(){
$params = $this->getRequest()->getParams();
//d($params);
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
$targ_w = $targ_h = 150;
$jpeg_quality = 90;
$src = $params['image_path'];
$img_r = imagecreatefromjpeg($src);
$dst_r = ImageCreateTrueColor( $targ_w, $targ_h );
$image = imagecopyresampled($dst_r,$img_r,0,0,$_POST['x'],$_POST['y'],$targ_w,$targ_h,$_POST['w'],$_POST['h']);
header('Content-type: image/jpeg');
imagejpeg($dst_r,null,$jpeg_quality);
exit;
}
}
I got the response as something like
��(��(��(��(��
Instead of cropped image, got some symbol. Need to get cropped image in ajax response. What i done wrong on this ?
You are sending the full image data back as response, instead save the image on the server and send the URL to it as a response
instead
header('Content-type: image/jpeg');
imagejpeg($dst_r,null,$jpeg_quality);
have this
imagejpeg($dst_r,"path/where/to/save/image.jpg",$jpeg_quality);
echo "path/where/to/save/image.jpg";
Also, your success function should look like
success : function(url) {
jQuery(".preview_crop").html('<img src="' + url + '" />');
}
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