Here is my code. I keep getting this error:
error: expected primary-expression before ')' token
Anyone have any ideas how to fix this?
void showInventory(player& obj) { // By Johnny :D
for(int i = 0; i < 20; i++) {
std::cout << "\nINVENTORY:\n" + obj.getItem(i);
i++;
std::cout << "\t\t\t" + obj.getItem(i) + "\n";
i++;
}
}
std::string toDo() //BY KEATON
{
std::string commands[5] = // This is the valid list of commands.
{"help", "inv"};
std::string ans;
std::cout << "\nWhat do you wish to do?\n>> ";
std::cin >> ans;
if(ans == commands[0]) {
helpMenu();
return NULL;
}
else if(ans == commands[1]) {
showInventory(player); // I get the error here.
return NULL;
}
}
This typically means that your code is missing a closing '}'. For every opening '{' there should be a closing '}' expected primary-expression before ')' token. Sometimes this happens when the variable passed into a function isn't the type the function expected.
You have to start with the first line and slowly fix every line. Compare your sketch with an example. There is no ';' after a #include, as you can see in a example from the DHT library that you use. Fix the 'define' or the 'const int' for the pin number, use an example to see how it is done.
– Adjust the Curly Braces To Fix the Expected Unqualified Id Error. You should match the opening and closing curly braces in your code to ensure the right quantity of brackets. The code should not have an extra or a missing curly bracket.
showInventory(player);
is passing a type as parameter. That's illegal, you need to pass an object.
For example, something like:
player p;
showInventory(p);
I'm guessing you have something like this:
int main()
{
player player;
toDo();
}
which is awful. First, don't name the object the same as your type. Second, in order for the object to be visible inside the function, you'll need to pass it as parameter:
int main()
{
player p;
toDo(p);
}
and
std::string toDo(player& p)
{
//....
showInventory(p);
//....
}
showInventory(player); // I get the error here.
void showInventory(player& obj) { // By Johnny :D
this means that player is an datatype and showInventory expect an referance to an variable of type player.
so the correct code will be
void showInventory(player& obj) { // By Johnny :D
for(int i = 0; i < 20; i++) {
std::cout << "\nINVENTORY:\n" + obj.getItem(i);
i++;
std::cout << "\t\t\t" + obj.getItem(i) + "\n";
i++;
}
}
players myPlayers[10];
std::string toDo() //BY KEATON
{
std::string commands[5] = // This is the valid list of commands.
{"help", "inv"};
std::string ans;
std::cout << "\nWhat do you wish to do?\n>> ";
std::cin >> ans;
if(ans == commands[0]) {
helpMenu();
return NULL;
}
else if(ans == commands[1]) {
showInventory(myPlayers[0]); // or any other index,also is not necessary to have an array
return NULL;
}
}
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