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I have a std::set<int>, what's the proper way to find the largest int in this set?
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The max_element() function returns an iterator to the largest element in the range [start,end).
Values of INT_MAX and INT_MIN may vary from compiler to compiler. Following are typical values in a compiler where integers are stored using 32 bits. Value of INT_MAX is +2147483647. Value of INT_MIN is -2147483648.
begin() and set. end() methods Approach: Elements in a set are stored in sorted order. So the minimum element of the set will reside in the first element and the maximum element in the last element. Therefore, this first and last element can be fetched with the help of set.
To find the max value for the unsigned integer data type, we take 2 to the power of 16 and substract by 1, which would is 65,535 . We get the number 16 from taking the number of bytes that assigned to the unsigned short int data type (2) and multiple it by the number of bits assigned to each byte (8) and get 16.
The int data type is the primary integer data type in SQL Server. The bigint data type is intended for use when integer values might exceed the range that is supported by the int data type.
Given a Set, the task is to find the maximum and minimum element of this set in C++ STL. Approach: Elements in a set are stored in sorted order. So the minimum element of the set will reside in the first element and the maximum element in the last element.
The INT function allows you to return the nearest integer less than or equal to a specified value. This will return 11. This will return -12. INT can be used in both TI’s and Rules. It works identically to the same function in Excel.
We use set in C++ STL. 1) Insert all elements into a set. 2) Traverse the set and print k-th element. Time complexity of above solution is O (n Log n). Note that set in STL uses a self-balancing BST internally and therefore time complexity of search and insert operations is O (log n).
What comparator are you using?
For the default this will work:
if(!myset.empty()) *myset.rbegin(); else //the set is empty This will also be constant time instead of linear like the max_element solution.
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