Logo Questions Linux Laravel Mysql Ubuntu Git Menu
 

How do i filter an array inside of a array of objects?

I'm trying to filter a list by tags:

const initialState = [
     {id:1 ,name: 'Product A', image: 'pic-001.jpg', tags: ['nature', 'camping', 'outdoor']},
     {id:2 ,name: 'Product B', image: 'pic-002.jpg', tags: ['winter', 'hiking', 'camping', 'snow']},
     {id:3 ,name: 'Product C', image: 'pic-003.jpg', tags: ['vacation', 'family', 'kids', 'river', 'lake', 'fishing']}
   ]

I can filter the list by name using map and filter, my problem is when i try to list the products by tags. Do i have to use foreach inside of my products filter? There's another way of doing it?

like image 351
Takebo Avatar asked Jul 06 '17 13:07

Takebo


Video Answer


2 Answers

Like that?

const filter = 'nature';
const filteredResult = initialState.filter((item) => {
    return (item.tags.indexOf(filter) >= 0);
});
like image 200
sjahan Avatar answered Oct 19 '22 11:10

sjahan


Firstly to get all the tags and filter the duplicate tags from initialState. Save the array into uniqueTags.

Then compare the uniqueTags with initialState names, to create another array productTags with objects and its properties tags and products.

const initialState = [
     {id:1 ,name: 'Product A', image: 'pic-001.jpg', tags: ['nature', 'camping', 'winter', 'outdoor']},
     {id:2 ,name: 'Product B', image: 'pic-002.jpg', tags: ['winter', 'hiking', 'family', 'camping', 'snow']},
     {id:3 ,name: 'Product C', image: 'pic-003.jpg', tags: ['vacation', 'family', 'kids', 'river', 'lake', 'fishing']}
   ]

   let allTags = [];
   initialState.map((t)=>t.tags).forEach((a)=>a.forEach((b)=>allTags.push(b)))
   let uniqueTags = allTags.filter((a,i,arr)=>arr.indexOf(a,i+1)===-1)


   productTags = [];
   uniqueTags.forEach((u)=>{
       initialState.forEach((t)=>{
           if(t.tags.includes(u))
            productTags.push({'tag': u, 'product':t.name});
       })
   })


   console.log(JSON.stringify(productTags));

   /*
   [
    { "tag": "nature", "product": "Product A" }, 
    { "tag": "outdoor", "product": "Product A" }, 
    { "tag": "winter", "product": "Product A" }, 
    { "tag": "winter", "product": "Product B" }, 
    { "tag": "hiking", "product": "Product B" }, 
    { "tag": "camping", "product": "Product A" }, 
    { "tag": "camping", "product": "Product B" }, 
    { "tag": "snow", "product": "Product B" }, 
    { "tag": "vacation", "product": "Product C" }, 
    { "tag": "family", "product": "Product B" }, 
    { "tag": "family", "product": "Product C" }, 
    { "tag": "kids", "product": "Product C" }, 
    { "tag": "river", "product": "Product C" }, 
    { "tag": "lake", "product": "Product C" }, 
    { "tag": "fishing", "product": "Product C" }
] */

(Edited later) Correction:

To form the correct object, I have changed the code to:

const initialState = [
     {id:1 ,name: 'Product A', image: 'pic-001.jpg', tags: ['nature', 'camping', 'winter', 'outdoor']},
     {id:2 ,name: 'Product B', image: 'pic-002.jpg', tags: ['winter', 'hiking', 'family', 'camping', 'snow']},
     {id:3 ,name: 'Product C', image: 'pic-003.jpg', tags: ['vacation', 'family', 'kids', 'river', 'lake', 'fishing']}
   ]

   let allTags = [];
   initialState.map((t)=>t.tags).forEach((a)=>a.forEach((b)=>allTags.push(b)))
   let uniqueTags = allTags.filter((a,i,arr)=>!arr.includes(a,i+1))


   productTags = [];
   uniqueTags.forEach((u)=>{
       let productName = [];
       initialState.forEach((t)=>{
           if(t.tags.includes(u))
            productName.push(t.name);
       })
       productTags.push({tag:u, products:productName}); 
   })

   console.log(JSON.stringify(productTags));

   /*
    productTags = [
        {"tag":"nature","products":["Product A"]},
        {"tag":"outdoor","products":["Product A"]},
        {"tag":"winter","products":["Product A","Product B"]},
        {"tag":"hiking","products":["Product B"]},
        {"tag":"camping","products":["Product A","Product B"]},
        {"tag":"snow","products":["Product B"]},
        {"tag":"vacation","products":["Product C"]},
        {"tag":"family","products":["Product B","Product C"]},
        {"tag":"kids","products":["Product C"]},
        {"tag":"river","products":["Product C"]},
        {"tag":"lake","products":["Product C"]},
        {"tag":"fishing","products":["Product C"]}
    ] 
    */
like image 44
Calvin Avatar answered Oct 19 '22 11:10

Calvin