var arr = [4, 5, 7, 8, 14, 45, 76]; function even(a) { var ar = []; for (var i = 0; i < a.length; i++) { ar.push(a[2 * i + 1]); } return ar; } alert(even(arr));
http://jsbin.com/unocar/2/edit
I have tried this code in order to output even (index) elements of an array. It works, but it also outputs some empty elements. How do I fix this code to output only existing elements?
Either use modulus:
for (var i = 0; i < a.length; i++) { if(i % 2 === 0) { // index is even ar.push(a[i]); } }
or skip every second element by incrementing i
accordingly:
for(var i = 0; i < a.length; i += 2) { // take every second element ar.push(a[i]); }
Notice: Your code actually takes the elements with odd indexes from the array. If this is what you want you have to use i % 2 === 1
or start the loop with var i = 1
respectively.
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