I'm writing a code to swap integers in an array and I want to know how I can exit a loop without using a break statement and keeping my logic consistent. Here is my code below:
int swapped = 0;
if (arrays[0][first] % 2 == 0)
{
cout << arrays[0][first] << " is odd " << endl;
for (int i = 1; i < arraycount; ++i)
{
for (int j = 1; j < arrays[i][0] + 1; ++j)
{
if (arrays[i][j] % 2 != 0)
{
int temp = arrays[i][j];
cout << "Array #" << 1 << " value " << arrays[0][first] << " swapped with "
<< "Array #" << i << " value " << temp;
arrays[i][j] = arrays[0][first];
arrays[0][first] = temp;
swapped = 1;
break;
}
}
if (swapped) {
break;
}
Use goto [I'll be bashed because of this].
if (arrays[0][first] % 2 == 0)
{
cout << arrays[0][first] << " is odd " << endl;
for (int i = 1; i < arraycount; ++i)
{
for (int j = 1; j < arrays[i][0] + 1; ++j)
{
if (arrays[i][j] % 2 != 0)
{
int temp = arrays[i][j];
cout << "Array #" << 1 << " value "
<< arrays[0][first] << " swapped with "
<< "Array #" << i << " value " << temp;
arrays[i][j] = arrays[0][first];
arrays[0][first] = temp;
goto done;
}
}
done:
something;
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