How do I execute several git commands in a batch file without terminating after the first command?

Question

I tried to put a series of GIT commands that I always use continuously togeter as batch files so that I don't repeat myself too much. For example, I have this batch file called update_repo_branch.bat to update a local repo and synch a branch with the remote branch:

@echo off
if(%1) == () goto end
if(%2) == () goto end
cd %1
git checkout %2
git fetch origin
git merge oring/%2
:end

Good to be lazy, but what I found is that when a GIT command is finished, it seems to send an exit flag back to terminate whatever is running. Therefore, using a batch file to exectute them all in one go simply doesn't work. Any idea how to work around it?

Answer 1

I'm not sure if this is true for all Windows git packages, but at least some use a git.cmd script as a wrapper around the actual git executables (for example git.exe). So when you're batch file uses a git command, Windows is actually running another batch file.

Unfortunately, when one batch file invokes another, by default it 'jumps' to the invoked batch file, never to return (this is for compatibility with ancient MS-DOS command processors or something).

You can solve this problem in a couple ways:

1. invoke git in your batch files using the call command to run the git.cmd batch file and return back to yours:

   call git checkout %2 call git fetch origin rem etc... 

2. invoke git in your batch file using the .exe extension explicitly to avoid the git.cmd batch file altogether. For this to work, you might need to make sure that you have your path and other environment variables set the way git.exe expects (that seems to be what git.cmd does in msysgit):

   git.exe checkout %2 rem etc...