How do I dynamically build an ng-include src?

Question

I have the following code:

<div ng-repeat="module in modules" id="{{module.Id}}">     <ng-include ng-init="bootstrapModule(module.Id)" src=""></ng-include> </div> 

I want to be able to build a string in src like so:

/modules/{{module.Name}}/{{module.Name}}.tpl.html 

But I keep hitting roadblocks. I've tried to use a call back function to build it,

$scope.constructTemplateUrl = function(id) {     return '/modules/' + id + '/' + id + '.tpl.html'; } 

But this gets called over & over & over and it doesn't seem to like that. I've also tried to construct it like so:

ng-src="/modules/{{module.Id}}/{{module.Id}}.tpl.html" 

But that isn't working either. Rather than spend hours beating around the bush, I wondered if anyone else has come up against something like this and has any ideas?

Also, when I grab the modules from $resource, I am returning them asynchronously with $q, so I can't seem to go through and add it into the modules before in the controller as $scope.modules just equals a then function at that point.

Any ideas?

Answer 1

ngInclude | src directive requires an angular expression, which means you should probably write

ng-src="'/modules/' + module.Id + '/tpl.html'"

From http://docs.angularjs.org/api/ng.directive:ngInclude

ngInclude|src string angular expression evaluating to URL. If the source is a string constant, make sure you wrap it in quotes, e.g. src="'myPartialTemplate.html'".

It might be better if you construct the url in model instead of inline HTML

<div ng-repeat="module in modules" id="{{module.Id}}">     <ng-include src="module.url"></ng-include> </div>