I am working on a slider that uses jQuery. Some elements of the slider are working correctly, but there is a problem that I am trying to troubleshoot with some of the code. To test it I would like to be able to display the values of the variables in the statement.
Here is the code block I am working with:
$('.marquee_nav a.marquee_nav_item').click(function(){
$('.marquee_nav a.marquee_nav_item').removeClass('selected');
$(this).addClass('selected');
var navClicked = $(this).index();
var marqueeWidth = $('.marquee_container').width();
var distanceToMove = marqueeWidth * (-1);
var newPhotoPosition = (navClicked * distanceToMove) + 'px';
var newCaption = $('.marquee_panel_caption').get(navClicked);
$(' .marquee_photos').animate({left: newPhotoPosition}, 1000);
});
I added a div called 'test' where I would like to display the values of the variables to make sure they are returning expected results:
<div class="test"><p>The value is: <span></span></p></div>
For example, to test the values, I inserted this into the statement above:
$('.test span').append(marqueeWidth);
However, I don't get any results. What is the correct way to include a test inside that code block to make sure I am getting the expected results?
Thanks.
Just use JavaScript's console
functions to log your variables within your browser's console.
var myVar = 123;
console.log(myVar, "Hello, world!");
If you're unsure how to open the console within your browser, see: https://webmasters.stackexchange.com/questions/8525/how-to-open-the-javascript-console-in-different-browsers
append
is used to append either an HTML string, a DOM element, an array of DOM elements, or a jQuery element. Since you are just trying to show a number (marqueeWidth
), you probably want to set the text
of the span instead:
$('.test span').text(marqueeWidth);
Also, is there a particular reason why you don't just use the console? It may be worth reading over a Debugging JavaScript walkthrough.
you can use the following.
$('.test span').html(marqueeWidth);
However doing a console.log(yourvariable);
or alert(yourvariable);
is better.
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