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In the Go language, is there any way to convert *string to string? (or, for that matter, any *T to T?)
I have looked on the internet and through some Go documentation, but I can't find it - may have missed it.
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As opposed to referencing a data value, a function pointer points to executable code within memory. Dereferencing the function pointer yields the referenced function, which can be invoked and passed arguments just as in a normal function call.
Go performs automatic dereferencing for struct data type in its specification. Hence, you do not need to de-reference it explicitly. Quote: As with selectors, a reference to a non-interface method with a value receiver using a pointer will automatically dereference that pointer: pt.Mv is equivalent to (*pt).
x is a pointer to a pointer to int. *x yields a int* (pointer to int ) **x = is like *(*x) = so you first obtain the pointer to int then by dereferencing you are able to set the value at the address.
In Go a pointer is represented using the * (asterisk) character followed by the type of the stored value. In the zero function xPtr is a pointer to an int . * is also used to “dereference” pointer variables. Dereferencing a pointer gives us access to the value the pointer points to.
To turn a *T into a T, use the * operator:
func Dereference(strptr *string) string {
return *strptr
}
I highly suggest you to read about pointers before proceeding with the language. They are a fundamental concept without which it is impossible to use the language efficiently.
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