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When I run this query:
START n1=node(7727), n2=node(7730)
MATCH n1-[r:SKILL]->n2 RETURN r
it gives me a list of duplicate relationships that I have between the two nodes. what do I add to the cypher query to iterate over the relationship to keep one relationship and delete the rest?
401
One option is to delete all relationships, then delete the node. Another option is to use the DETACH DELETE clause. The DETACH DELETE clause lets you delete a node and all relationships connected to it.
To delete all but one of the duplicate nodes, you could do this: MATCH (b:BusinessBranch) WITH b. address AS address, COLLECT(b) AS branches WHERE SIZE(branches) > 1 FOREACH (n IN TAIL(branches) | DETACH DELETE n); However, in this case you should first take a look at the APOC procedure apoc.
To do this for two known nodes:
start n=node(1), m=node(2) match (n)-[r]->(m)
with n,m,type(r) as t, tail(collect(r)) as coll
foreach(x in coll | delete x)
To do this globally for all relationships (be warned this operation might be very expensive depending on the size of your graph):
start r=relationship(*)
match (s)-[r]->(e)
with s,e,type(r) as typ, tail(collect(r)) as coll
foreach(x in coll | delete x)
With Neo4J 4.x and to globally remove duplicate relationships, you'll want to use the following instead. The syntax has changed slightly and the start prefix mentioned in the other reply no longer works.
match ()-[r]->()
match (s)-[r]->(e)
with s,e,type(r) as typ, tail(collect(r)) as coll
foreach(x in coll | delete x)
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