To interactively test my python script, I would like to create a Namespace
object, similar to what would be returned by argparse.parse_args()
. The obvious way,
>>> import argparse >>> parser = argparse.ArgumentParser() >>> parser.parse_args() Namespace() >>> parser.parse_args("-a") usage: [-h] : error: unrecognized arguments: - a Process Python exited abnormally with code 2
may result in Python repl exiting (as above) on a silly error.
So, what is the easiest way to create a Python namespace with a given set of attributes?
E.g., I can create a dict
on the fly (dict([("a",1),("b","c")])
) but I cannot use it as a Namespace
:
AttributeError: 'dict' object has no attribute 'a'
So if you want to create a namespace, you just need to call a function, instantiate an object, import a module or import a package. For example, we can create a class called Namespace and when you create an object of that class, you're basically creating a namespace.
The parse_args() method actually returns some data from the options specified, in this case, echo . The variable is some form of 'magic' that argparse performs for free (i.e. no need to specify which variable that value is stored in).
A namespace is a system that has a unique name for each and every object in Python. An object might be a variable or a method. Python itself maintains a namespace in the form of a Python dictionary.
You can create a simple class:
class Namespace: def __init__(self, **kwargs): self.__dict__.update(kwargs)
and it'll work the exact same way as the argparse
Namespace
class when it comes to attributes:
>>> args = Namespace(a=1, b='c') >>> args.a 1 >>> args.b 'c'
Alternatively, just import the class; it is available from the argparse
module:
from argparse import Namespace args = Namespace(a=1, b='c')
As of Python 3.3, there is also types.SimpleNamespace
, which essentially does the same thing:
>>> from types import SimpleNamespace >>> args = SimpleNamespace(a=1, b='c') >>> args.a 1 >>> args.b 'c'
The two types are distinct; SimpleNamespace
is primarily used for the sys.implementation
attribute and the return value of time.get_clock_info()
.
Further comparisons:
instance_a == instance_b
is true if they have the same attributes with the same values.__repr__
to show what attributes they have.Namespace()
objects support containment testing; 'attrname' in instance
is true if the namespace instance has an attribute namend attrname
. SimpleNamespace
does not.Namespace()
objects have an undocumented ._get_kwargs()
method that returns a sorted list of (name, value)
attributes for that instance. You can get the same for either class using sorted(vars(instance).items())
.SimpleNamespace()
is implemented in C and Namespace()
is implemented in Python, attribute access is no faster because both use the same __dict__
storage for the attributes. Equality testing and producing the representation are a little faster for SimpleNamespace()
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