How do I count the trailing zeros in integer?

Question

I am trying to write a function that returns the number of trailing 0s in a string or integer. Here is what I am trying and it is not returning the correct values.

def trailing_zeros(longint):
    manipulandum = str(longint)
    x = 0
    i = 1
    for ch in manipulandum:
        if manipulandum[-i] == '0':
            x += x
            i += 1
        else:
            return x

Answer 1

For strings, it is probably the easiest to use rstrip():

In [2]: s = '23989800000'

In [3]: len(s) - len(s.rstrip('0'))
Out[3]: 5

Answer 2

May be you can try doing this. This may be easier than counting each trailing '0's

def trailing_zeros(longint):
    manipulandum = str(longint)
    return len(manipulandum)-len(manipulandum.rstrip('0'))