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How do I convert uint to int in C#?

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c#

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How do you convert units to integers?

uint asUint = checked((uint)myInt); int asInt = checked((int)myUint); In this case, you'll get overflow exceptions if: casting a negative int (eg: -1) to an uint. casting a positive uint between 2,147,483,648 and 4,294,967,295 to an int.

How do I convert unsigned to signed int?

To convert a signed integer to an unsigned integer, or to convert an unsigned integer to a signed integer you need only use a cast. For example: int a = 6; unsigned int b; int c; b = (unsigned int)a; c = (int)b; Actually in many cases you can dispense with the cast.

How do you make an unsigned integer?

For most purposes, all integers in Java are signed. However, you can treat a signed integer as unsigned in one specific case: you can shift right without sign extending by using >>> operator instead of >> .

Is it safe to cast int to Uint?

Casting from int , uint , or long to a float could result in the loss of precision, but never magnitude. Casting from long to a double could result in the loss of precision, but never magnitude.


Given:

 uint n = 3;

int i = checked((int)n); //throws OverflowException if n > Int32.MaxValue
int i = unchecked((int)n); //converts the bits only 
                           //i will be negative if n > Int32.MaxValue

int i = (int)n; //same behavior as unchecked

or

int i = Convert.ToInt32(n); //same behavior as checked

--EDIT

Included info as mentioned by Kenan E. K.


Assuming you want to simply lift the 32bits from one type and dump them as-is into the other type:

uint asUint = unchecked((uint)myInt);
int asInt = unchecked((int)myUint);

The destination type will blindly pick the 32 bits and reinterpret them.

Conversely if you're more interested in keeping the decimal/numerical values within the range of the destination type itself:

uint asUint = checked((uint)myInt);
int asInt = checked((int)myUint);

In this case, you'll get overflow exceptions if:

  • casting a negative int (eg: -1) to an uint
  • casting a positive uint between 2,147,483,648 and 4,294,967,295 to an int

In our case, we wanted the unchecked solution to preserve the 32bits as-is, so here are some examples:

Examples

int => uint

int....: 0000000000 (00-00-00-00)
asUint.: 0000000000 (00-00-00-00)
------------------------------
int....: 0000000001 (01-00-00-00)
asUint.: 0000000001 (01-00-00-00)
------------------------------
int....: -0000000001 (FF-FF-FF-FF)
asUint.: 4294967295 (FF-FF-FF-FF)
------------------------------
int....: 2147483647 (FF-FF-FF-7F)
asUint.: 2147483647 (FF-FF-FF-7F)
------------------------------
int....: -2147483648 (00-00-00-80)
asUint.: 2147483648 (00-00-00-80)

uint => int

uint...: 0000000000 (00-00-00-00)
asInt..: 0000000000 (00-00-00-00)
------------------------------
uint...: 0000000001 (01-00-00-00)
asInt..: 0000000001 (01-00-00-00)
------------------------------
uint...: 2147483647 (FF-FF-FF-7F)
asInt..: 2147483647 (FF-FF-FF-7F)
------------------------------
uint...: 4294967295 (FF-FF-FF-FF)
asInt..: -0000000001 (FF-FF-FF-FF)
------------------------------

Code

int[] testInts = { 0, 1, -1, int.MaxValue, int.MinValue };
uint[] testUints = { uint.MinValue, 1, uint.MaxValue / 2, uint.MaxValue };

foreach (var Int in testInts)
{
    uint asUint = unchecked((uint)Int);
    Console.WriteLine("int....: {0:D10} ({1})", Int, BitConverter.ToString(BitConverter.GetBytes(Int)));
    Console.WriteLine("asUint.: {0:D10} ({1})", asUint, BitConverter.ToString(BitConverter.GetBytes(asUint)));
    Console.WriteLine(new string('-',30));
}
Console.WriteLine(new string('=', 30));
foreach (var Uint in testUints)
{
    int asInt = unchecked((int)Uint);
    Console.WriteLine("uint...: {0:D10} ({1})", Uint, BitConverter.ToString(BitConverter.GetBytes(Uint)));
    Console.WriteLine("asInt..: {0:D10} ({1})", asInt, BitConverter.ToString(BitConverter.GetBytes(asInt)));
    Console.WriteLine(new string('-', 30));
}  

Take note of the checked and unchecked keywords.

It matters if you want the result truncated to the int or an exception raised if the result doesnt fit in signed 32 bits. The default is unchecked.


Convert.ToInt32() takes uint as a value.


uint i = 10;
int j = (int)i;

or

int k = Convert.ToInt32(i)