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How do I convert a Block to a Proc in a Ruby 1.9 C extension?

I'm writing a Ruby 1.9 C extension and I want to do the following in ruby:

notifier = Notifier.new
notifier.on 'click' do
  puts "clicked!"
end

Now the problem with this is that on the C method, I only "receive" a block, and, as far as I know, it's not even a parameter: I just can call with with rb_yield.

So my question is: is there a way on a Ruby 1.9 C extension, to transform a block into a proc or something, so I can store it inside my module, and call it later whenever I want/need them? Like an async callback!

I already implemented this with Procs/lambdas, but it's just ugly not to use the block syntax directly.

like image 869
rubenfonseca Avatar asked Jan 17 '12 22:01

rubenfonseca


1 Answers

In the Ruby C source you'll see this in proc.c:

/*
 * call-seq:
 *   proc   { |...| block }  -> a_proc
 *
 * Equivalent to <code>Proc.new</code>.
 */

VALUE
rb_block_proc(void)
{
    return proc_new(rb_cProc, FALSE);
}

and Proc.new does this:

Creates a new Proc object, bound to the current context. Proc::new may be called without a block only within a method with an attached block, in which case that block is converted to the Proc object.

So you'd do something like this:

VALUE p = rb_block_proc();
/* and then store `p` somewhere convenient */

and then later on, to call the block/Proc:

rb_funcall(p, rb_intern("call"), 0);

That rb_funcall is pretty much the C version of p.send(:call).

like image 72
mu is too short Avatar answered Oct 13 '22 01:10

mu is too short