How do I compare each character of a String while accounting for characters with length > 1?

Question

I have a variable string that might contain any unicode character. One of these unicode characters is the han 𩸽.

The thing is that this "han" character has "𩸽".length() == 2 but is written in the string as a single character.

Considering the code below, how would I iterate over all characters and compare each one while considering the fact it might contain one character with length greater than 1?

for ( int i = 0; i < string.length(); i++ ) {
    char character = string.charAt( i );
    if ( character == '𩸽' ) {
        // Fail, it interprets as 2 chars =/
    }
}

EDIT:
This question is not a duplicate. This asks how to iterate for each character of a String while considering characters that contains .length() > 1 (character not as a char type but as the representation of a written symbol). This question does not require previous knowledge of how to iterate over unicode code points of a Java String, although an answer mentioning that may also be correct.

Answer 1

int hanCodePoint = "𩸽".codePointAt(0);
for (int i = 0; i < string.length();) {
    int currentCodePoint = string.codePointAt(i);
    if (currentCodePoint == hanCodePoint) {
        // do something here.
    }
    i += Character.charCount(currentCodePoint);
}