Here's a rather elementary *nix question:
Given the following symlink creation:
ln -s /usr/local/projects/myproject/ myproject
... from my home directory /home/jvf/, entering the myproject symlink gives me a pwd /home/jfv/myproject/. Now, I would like to enter the parent directory of the directory I've symlinked to, but the cd .. command will only bring me back to my home directory /home/jfv/. Is there anyway to escape the symlink trail that I've entered, and instead have a pwd equal to the actual path of the myproject directory. That is, changing my pwd from /home/jfv/myproject/ into /usr/local/projects/myproject/?
Thanks :)
You can create a symlink to a directory that doesn't exist, but you can't then "cd" into it... the source directory still doesn't exist. :) You can, however, make a symlink to a non-existent file and then edit that the file through the symlink. The source file will appear when you save, just like editing any new file.
Just use -P
(physical) flag:
pwd -P cd -P ..
If you do the following you should be OK.
1) First you follow your symlink:
[jfv@localhost ~]$ cd myproject
2) Now you execute the following command:
[jfv@localhost myproject]$ cd -P ./
3) Now, you can check your location and you will see that you are on the physical directory
[jfv@localhost myproject]$ pwd
The output will be as follows:
/usr/local/projects/myproject
Now, everything you do will be local and not on the symlink.
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