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I am trying to parse a list of email addresses to remove the username and '@' symbol only leaving the domain name.
Example: [email protected] Desired output: gmail.com
I have accomplished this with the following code:
for row in cr:
emailaddy = row[0]
(emailuser, domain) = row[0].split('@')
print domain
but my issue is when I encounter a improperly formatted email address. For example if the row contains "aaaaaaaaa" (instead of a valid email address) the program crashes with the error
(emailuser, domain) = row[0].split('@')
ValueError: need more than 1 value to unpack.
(as you would expect) Rather than check all the email addresses for their validity, I would rather just not update grab the domain and move on to the next record. How can I properly handle this error and just move on?
So for the list of:
[email protected]
[email protected]
youououou
[email protected]
I would like the output to be:
gmail.com
hotmail.com
yahoo.com
Thanks!
470
Definition and Usage. The split() method splits a string into a list. You can specify the separator, default separator is any whitespace. Note: When maxsplit is specified, the list will contain the specified number of elements plus one.
By handling multiple exceptions, a program can respond to different exceptions without terminating it. In Python, try-except blocks can be used to catch and respond to one or multiple exceptions. In cases where a process raises more than one possible exception, they can all be handled using a single except clause.
Try and Except Statement – Catching all Exceptions Try and except statements are used to catch and handle exceptions in Python. Statements that can raise exceptions are kept inside the try clause and the statements that handle the exception are written inside except clause.
Description. Python string method split() returns a list of all the words in the string, using str as the separator (splits on all whitespace if left unspecified), optionally limiting the number of splits to num.
You can just filter out the address which does not contain @.
>>> [mail.split('@')[1] for mail in mylist if '@' in mail]
['gmail.com', 'hotmail.com', 'yahoo.com']
>>>
What about
splitaddr = row[0].split('@')
if len(splitaddr) == 2:
domain = splitaddr[1]
else:
domain = ''
This even handles cases like aaa@bbb@ccc and makes it invalid ('').
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