My code is:
hash = { two: 2, three: 3 }
def hash_add(hash, new_key, new_value)
temp_hash = {}
temp_hash[new_key.to_sym] = new_value
temp_hash.merge!(hash)
hash = temp_hash
puts hash
end
hash_add(hash, 'one', 1)
Within the method, puts hash
returns { :one => 1, :two => 2, :three => 3 }
, but when hash1
is put to the method, it remains unchanged afterward. It's like the assignment isn't carrying itself outside of the function.
I guess I could return the updated hash and set the hash I want to change to it outside the method:
hash = hash_add(hash, 'one', 1)
But I just don't see why the assignment I give to the hash does not stick outside of the method.
I have this, which works:
def hash_add(hash, new_key, new_value)
temp_hash = {}
temp_hash[new_key.to_sym] = new_value
temp_hash.merge!(hash)
hash.clear
temp_hash.each do |key, value|
hash[key] = value
end
end
Which gives me what I'm wanting when this method is called, but it just seems a little excessive to have to rebuild the hash like that.
How about this?
hash1 = { two: 2, three: 3 }
#add a new key,value
hash1 = Hash[:one,1].merge!(hash1) #=> {:one=>1, :two=>2, :three=>3}
Example #2:
h = { two: 2, three: 3 }
def hash_add(h,k,v)
Hash[k.to_sym,v].merge!(h)
end
h = hash_add(h, 'one', 1) #=> {:one=>1, :two=>2, :three=>3}
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