I have a table that is generated on the fly, as it is generating its TDs, I want to set the first TD to be a button. Below is my code, obviously doesn't work. I remember from another problem I had that we can change the content of a div using the .html(), but that doesnt work here neither.
Code:
var table = document.getElementById("userinfo");
var thead, tr, td;
table.appendChild(thead = document.createElement("thead"));
thead.appendChild(tr = document.createElement("tr"));
tr.appendChild(td = document.createElement("td"));
td.innerHTML = "Email";
tr.appendChild(td = document.createElement("td"));
td.innerHTML = "First Name";
tr.appendChild(td = document.createElement("td"));
td.innerHTML = "Last Name";
tr.appendChild(td = document.createElement("td"));
td.innerHTML = "Is Active?";
for (var i in data)
{
tr = document.createElement("tr");
tr.setAttribute("id", "row" + i);
if (i%2 == 0)
{
tr.setAttribute("style", "background:white");
}
var entry = data[i];
console.log(entry);
table.appendChild(tr);
tr.appendChild(td = document.createElement("td"));
td.setAttribute("html", "<input type=\"button\" class=\"btn\" value=\'" + entry.email + "\" onclick=\"" + chooseUser(entry) + "\"/>");
tr.appendChild(td = document.createElement("td"));
td.innerHTML = entry.first_name;
tr.appendChild(td = document.createElement("td"));
td.innerHTML = entry.last_name;
tr.appendChild(td = document.createElement("td"));
td.innerHTML = entry.isActive;
}
You can either use td.innerHTML = '<input type="button"...';
or you can do it the "proper" way:
var btn = document.createElement('input');
btn.type = "button";
btn.className = "btn";
btn.value = entry.email;
btn.onclick = (function(entry) {return function() {chooseUser(entry);}})(entry);
td.appendChild(btn);
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