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How do I access properties of a javascript object if I don't know the names?

Say you have a javascript object like this:

var data = { foo: 'bar', baz: 'quux' };

You can access the properties by the property name:

var foo = data.foo;
var baz = data["baz"];

But is it possible to get these values if you don't know the name of the properties? Does the unordered nature of these properties make it impossible to tell them apart?

In my case I'm thinking specifically of a situation where a function needs to accept a series of name-value pairs, but the names of the properties may change.

My thoughts on how to do this so far is to pass the names of the properties to the function along with the data, but this feels like a hack. I would prefer to do this with introspection if possible.

like image 990
Adam Lassek Avatar asked Oct 20 '22 13:10

Adam Lassek


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1 Answers

You can loop through keys like this:

for (var key in data) {
  console.log(key);
}

This logs "Name" and "Value".

If you have a more complex object type (not just a plain hash-like object, as in the original question), you'll want to only loop through keys that belong to the object itself, as opposed to keys on the object's prototype:

for (var key in data) {
  if (data.hasOwnProperty(key)) {
    console.log(key);
  }
}

As you noted, keys are not guaranteed to be in any particular order. Note how this differs from the following:

for each (var value in data) {
  console.log(value);
}

This example loops through values, so it would log Property Name and 0. N.B.: The for each syntax is mostly only supported in Firefox, but not in other browsers.

If your target browsers support ES5, or your site includes es5-shim.js (recommended), you can also use Object.keys:

var data = { Name: 'Property Name', Value: '0' };
console.log(Object.keys(data)); // => ["Name", "Value"]

and loop with Array.prototype.forEach:

Object.keys(data).forEach(function (key) {
  console.log(data[key]);
});
// => Logs "Property Name", 0
like image 145
Ron DeVera Avatar answered Oct 24 '22 07:10

Ron DeVera