I just learnt about Enums and Types in Ada and decided to write a small program to practice:
with Ada.Text_IO; use Ada.Text_IO;
with Ada.Integer_Text_IO; use Ada.Integer_Text_IO;
procedure Day is
type Day_Of_The_Week is (Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, Sunday);
subtype Weekday is Day_Of_The_Week range Monday..Friday;
subtype Weekend is Day_Of_The_Week range Saturday..Sunday;
function is_Weekday ( dayOfTheWeek: in Day_Of_The_Week) return Boolean is
begin
if(--?--)
end is_Weekday;
selected_day_value : Integer;
selected_day : Day_Of_The_Week;
begin
Put_Line("Enter the number co-responding to the desired day of the week:");
Put_Line("0 - Monday");
Put_Line("1 - Tuesday");
Put_Line("2 - Wednesday");
Put_Line("3 - Thursday");
Put_Line("4 - Friday");
Put_Line("5 - Saturday");
Put_Line("6 - Sunday");
Get(selected_day_value);
selected_day = Day_Of_The_Week'pos(selected_day_value);
if( is_Weekday(selected_day))
Put_Line( Day_Of_The_Week'Image(selected_day) & " is a weekday." );
else
Put_Line( Day_Of_The_Week'Image(selected_day) & " is a weekday." );
end Day;
I'm having trouble with the if statement. How can I check whether or not dayOfTheWeek is in the Weekday subtype or the weekend subtype?
You want
function is_Weekday ( dayOfTheWeek: in Day_Of_The_Week) return Boolean is
begin
return dayoFTheWeek in Weekday;
end is_Weekday;
Also, you want ’Val
not ’Pos
in
selected_day := Day_Of_The_Week'val(selected_day_value);
and you might take a look at the words in the second Put_Line
!
You don't need a function to check for this. In this case a function only obscures what happens:
if Selected_Day in Weekday then
do stuff..
else
do other stuff...
end if;
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