How can type safety be guarded against implicit conversion in Java?

Question

Suppose a method is as following:

void foo(int i)
{
}

Is there a way to make the following call illegal or generate an exception?

foo((short)3);

Answer 1

Maybe this?

class AClass {
  void foo(int x) { /* do work */ }
  void foo(short x) { throw new IllegalArgumentException(); }
}

Answer 2

Bruno's overloading will work, but if you are looking at preventing other types of casting, you can always box the integer into its Object class:

void foo(Integer i) {
    // handle data normally
}

This will prevent you from being able to send short arguments to it.