html file through a browser, the client will be able to upload a file to the server using Ajax and pure JavaScript. A pure JavaScript file uploader simplifies Ajax based interactions with the server.
Select an image from the images folder to upload then select the Upload! button. The React front-end client code calls into the ./src/azure-storage-blob. ts to authenticate to Azure, then create a Storage Container (if it doesn't already exist), then uploads the file to that container.
You can use the FormData API.
If you're using jquery.ajax
, you need to set processData: false
and contentType: false
.
var fd = new FormData();
fd.append('fname', 'test.wav');
fd.append('data', soundBlob);
$.ajax({
type: 'POST',
url: '/upload.php',
data: fd,
processData: false,
contentType: false
}).done(function(data) {
console.log(data);
});
This updates the answers with the latest Fetch API and doesn't need jQuery.
Disclaimer: doesn't work on IE, Opera Mini and older browsers. See caniuse.
Basic Fetch
It could be as simple as:
fetch(`https://example.com/upload.php`, {method:"POST", body:blobData})
.then(response => console.log(response.text()))
Fetch with Error Handling
After adding error handling, it could look like:
fetch(`https://example.com/upload.php`, {method:"POST", body:blobData})
.then(response => {
if (response.ok) return response;
else throw Error(`Server returned ${response.status}: ${response.statusText}`)
})
.then(response => console.log(response.text()))
.catch(err => {
alert(err);
});
PHP Code
This is the server-side code in upload.php.
<?php
// gets entire POST body
$data = file_get_contents('php://input');
// write the data out to the file
$fp = fopen("path/to/file", "wb");
fwrite($fp, $data);
fclose($fp);
?>
You actually don't have to use FormData
to send a Blob
to the server from JavaScript (and a File
is also a Blob
).
jQuery example:
var file = $('#fileInput').get(0).files.item(0); // instance of File
$.ajax({
type: 'POST',
url: 'upload.php',
data: file,
contentType: 'application/my-binary-type', // set accordingly
processData: false
});
Vanilla JavaScript example:
var file = $('#fileInput').get(0).files.item(0); // instance of File
var xhr = new XMLHttpRequest();
xhr.open('POST', '/upload.php', true);
xhr.onload = function(e) { ... };
xhr.send(file);
Granted, if you are replacing a traditional HTML multipart form with an "AJAX" implementation (that is, your back-end consumes multipart form data), you want to use the FormData
object as described in another answer.
Source: New Tricks in XMLHttpRequest2 | HTML5 Rocks
I could not get the above example to work with blobs and I wanted to know what exactly is in upload.php. So here you go:
(tested only in Chrome 28.0.1500.95)
// javascript function that uploads a blob to upload.php
function uploadBlob(){
// create a blob here for testing
var blob = new Blob(["i am a blob"]);
//var blob = yourAudioBlobCapturedFromWebAudioAPI;// for example
var reader = new FileReader();
// this function is triggered once a call to readAsDataURL returns
reader.onload = function(event){
var fd = new FormData();
fd.append('fname', 'test.txt');
fd.append('data', event.target.result);
$.ajax({
type: 'POST',
url: 'upload.php',
data: fd,
processData: false,
contentType: false
}).done(function(data) {
// print the output from the upload.php script
console.log(data);
});
};
// trigger the read from the reader...
reader.readAsDataURL(blob);
}
The contents of upload.php:
<?
// pull the raw binary data from the POST array
$data = substr($_POST['data'], strpos($_POST['data'], ",") + 1);
// decode it
$decodedData = base64_decode($data);
// print out the raw data,
echo ($decodedData);
$filename = "test.txt";
// write the data out to the file
$fp = fopen($filename, 'wb');
fwrite($fp, $decodedData);
fclose($fp);
?>
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