How can I use python's argparse with a predefined argument string?

Question

I want to use the pythons argparse module to parse my cli parameter string. This works for the parameters a pass from terminal, but not with a given string.

import argparse  parser = argparse.ArgumentParser(description='Argparse Test script') parser.add_argument("param", help='some parameter')  argString = 'someTestFile' print(argString)  args = parser.parse_args(argString) 

If I run this script I get this output:

~/someTestFile usage: argparsetest.py [-h] param argparsetest.py: error: unrecognized arguments: o m e T e s t F i l e 

The ~/someTestFile is somehow transformed in o m e T e s t F i l e. As already mentioned, it works if I pass the filename from the terminal.

I could imagine, that this has something to do with string encodings. Does someone has an idea how to fix this?

Answer 1

Another option is to use shlex.split. It it especially very convenient if you have real CLI arguments string:

import shlex argString = '-vvvv -c "yes" --foo bar --some_flag' args = parser.parse_args(shlex.split(argString)) 

Answer 2

parser.parse_args() expects a sequence in the same form as sys.argv[1:]. If you treat a string like a sys.argv sequence, you get ['s', 'o', 'm', 'e', 'T', 'e', 's', 't', 'F', 'i', 'l', 'e']. 's' becomes the relevant argument, and then the rest of the string is unparseable.

Instead, you probably want to pass in parser.parse_args(['someTestFile'])