In my code I need to be able to jump (goto) a different case within the same switch statement. Is there a way to do this?
My code is something like this: (There is a lot of code I just left it all out)
switch (viewNumber) {
case 500:
// [...]
break;
case 501:
// [...]
break;
.
.
.
.
.
case 510:
// [...]
break;
default:
break;
}
Thank you for your time! -Jeff
It's generally very bad practice to unconditionally jump like you're asking.
I think a more readable/maintainable solution would be to place the shared code in a method and have multiple cases call the method.
If you really want to, you can use goto
to do something like:
switch(viewNumber) {
case 500:
// [...]
goto jumpLabel;
case 501:
// [...]
break;
case 502:
// [...]
jumpLabel:
// Code that 500 also will execute
break;
default:break;
}
Note: I only provided the code example above to answer your question. I now feel so dirty I might have to buy some Bad Code Offsets.
Instead of using goto
, refactor your code so that the two (or more) cases that use common code instead call it in a common method.
Something like:
switch (value) {
case (firstValue):
// ...
break;
case (secondValue):
[self doSharedCodeForSecondAndThirdValues];
break;
case (thirdValue):
[self doSharedCodeForSecondAndThirdValues];
break;
default:
break;
}
// ...
- (void) doSharedCodeForSecondAndThirdValues {
// do stuff here that is common to second and third value cases
}
It wouldn't be the end of the world to use goto
, though it is bad practice.
The practical reason for avoiding use of goto
is that you have to search through your swtich-case
tree to find that goto
label.
If your switch logic changes, you'll have a messy situation on your hands.
If you pull out common code to its own method, the code is easier to read, debug and extend.
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