I'm trying to spawn multiple processes at once in PHP with proc_open, but the second call won't start until the first process has ended. Here's the code I'm using:
for ($i = 0; $i < 2; $i++)
{
$cmdline = "sleep 5";
print $cmdline . "\n";
$descriptors = array(0 => array('file', '/dev/null', 'r'),
1 => array('file', '/dev/null', 'w'),
2 => array('file', '/dev/null', 'w'));
$proc = proc_open($cmdline, $descriptors, $pipes);
print "opened\n";
}
Others are pointing out alternatives, but your actual problem is likely the leaking of your $proc variable. I believe PHP has to keep track of this and if you are overwriting it, it will clean up for you (which means proc_close, which means waiting...)
Try not leaking the $proc value:
<?php
$procs = array();
for ($i = 0; $i < 2; $i++)
{
$cmdline = "sleep 5";
print $cmdline . "\n";
$descriptors = array(0 => array('file', '/dev/null', 'r'),
1 => array('file', '/dev/null', 'w'),
2 => array('file', '/dev/null', 'w'));
$procs[]= proc_open($cmdline, $descriptors, $pipes);
print "opened\n";
}
?>
Note: This will still clean up your process handles before exiting, so all processes will have to complete first. You should use proc_close
after you are done doing whatever you need to do with these (ie: read pipes, etc). If what you really want is to launch them and forget about them, that is a different solution.
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