How can I replace a variable in a string with the value in PHP?

Question

I have string like this in database (the actual string contains 100s of word and 10s of variable):

I am a {$club} fan 

I echo this string like this:

$club = "Barcelona"; echo $data_base[0]['body']; 

My output is I am a {$club} fan. I want I am a Barcelona fan. How can I do this?

Answer 1

Use strtr. It will translate parts of a string.

$club = "Barcelona"; echo strtr($data_base[0]['body'], array('{$club}' => $club)); 

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For multiple values (demo):

$data_base[0]['body'] = 'I am a {$club} fan.'; // Tests  $vars = array(   '{$club}'       => 'Barcelona',   '{$tag}'        => 'sometext',   '{$anothertag}' => 'someothertext' );  echo strtr($data_base[0]['body'], $vars); 

Program Output:

I am a Barcelona fan. 

Answer 2

/**  * A function to fill the template with variables, returns filled template.  *  * @param string $template A template with variables placeholders {$variable}.  * @param array $variables A key => value store of variable names and values.  *  * @return string  */  public function replaceVariablesInTemplate($template, array $variables){   return preg_replace_callback('#{(.*?)}#',        function($match) use ($variables){             $match[1] = trim($match[1], '$');             return $variables[$match[1]];        },        ' ' . $template . ' '); }